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Raymond is 6 years older than his sister. Four years from now, Raymond will be twice as old as his sister.
Find their present ages.
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In 4 years from now, Raymond will be 6 years older than his sister, and, AT THE SAME TIME,
will be twice as old as she.
Then it becomes clear that in 6 years Raymond is 12 years old, while the sister is 6 years old.
So, now their current ages are 12-4 = 8 years (Raymond) and 6-4 = 2 years (the sister). ANSWER
Solved (mentally, without using equations).
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There is a bunch of lessons on age word problems
- Age problems and their solutions
- HOW TO algebreze and to solve age problems?
- A fresh formulation of a traditional age problem
- Really intricate age word problems
- Selected age word problems from the archive
- Age problems for mental solution
- Age problem for three participants
- Miscellaneous age problems
in this site.
Read them and become an expert in solving age problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Age word problems".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.