SOLUTION: Allison is seven less than three times the age of Jennifer. Six years ago, one-fourth of the age of Allison is equal to the age of Jennifer was then. Find their present ages.

Question 1178593: Allison is seven less than three times the age of Jennifer. Six years ago, one-fourth of the age of Allison is equal to the age of Jennifer was then. Find their present ages.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Allison age = a
jennifer age =j
Allison is seven less than three times the age of Jennifer.
a=3j-7
a-3j =-7
Six years ago, one-fourth of the age of Allison is equal to the age of Jennifer
was then.
1/4 (a-6) = j-6
a-6 = 4j-24
a-4j =-18
a-3j=-7
subtract
-j=-11
Jennifer's age =11 years
Allison's age ---> a=3j-7
=26 years

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