Question 1173704: Marvin is 22 years older than his younger brother Raul. In 6 years, the sum of their ages will be 60. How old is each?
Found 3 solutions by VFBundy, mila nedic, MathTherapy:Answer by VFBundy(438) (Show Source): You can put this solution on YOUR website! Raul's age = x
Marvin's age = x + 22
(x + 6) + (x + 22 + 6) = 60
2x + 34 = 60
2x = 26
x = 13
Raul's age = x = 13
Marvin's age = x + 22 = 35 Answer by mila nedic(19) (Show Source): You can put this solution on YOUR website! Let's say Marvin's age is m and Raul's age is r. We can make equations using these variables with the two pieced of information.
Marvin is 22 years older that Raul: m=r+22
In six year the sum of their ages will be 60: (m+6)+(r+6)=60
m=r+22
((r+22)+6)+(r+6)=60 (since we know that m=r+22 we can replace m with r+22 so we are only dealing with one variable)
r+28+r+6=60
2r+34=60
2r=26
r=13 (now we know that Raul is 13)
We can use one of the original equations to find our Marvin's age.
m=r+22
m=13+22 (we can replace r with 13)
m=35 (Marvin is 35)
To check our work we can use the second equation to see if the ages are correct.
(m+6)+(r+6)=60
(35+6)+(13+6)=60
60=60 (the left side of the equation is equal to 60 and so is the right side, we know our ages are correct)
Therefore Marvin is 35 years old and Raul is 13 years old. Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website! Marvin is 22 years older than his younger brother Raul. In 6 years, the sum of their ages will be 60. How old is each?
Let Raul's age be R
Then Marvin's is: R + 22
We then get: R + R + 22 + 2(6) = 60
2R + 34 = 60
2R = 26
Raul, or
You shouldn't have any problems finding Marvin's age now!