SOLUTION: Five years ago, jay was 7 years more than one half as old as fred. the product of their ages is 696. find their present ages
Algebra.Com
Question 1170470: Five years ago, jay was 7 years more than one half as old as fred. the product of their ages is 696. find their present ages
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Jay, 24
Fred, 29
---------
---------
.
.
.
discriminant, , ;
-
,
RELATED QUESTIONS
Here is my problem Five years ago, jay was 7 years more than as half as old as fred. The... (answered by Alan3354,josmiceli)
The age of Tim is 1 year more than twice of Carla's age. Three years ago, he was thrice... (answered by thinktank.experts)
Carlo is half as old as Raul. James is 6 years older than Carlo. Four years ago, the sum (answered by Boreal)
Cora is twice old as her sister Maria. The quotient of their ages five years ago was... (answered by MathTherapy)
please help me with this
Adam is 3 times as old as cynthia and Fred is 16 years younger (answered by Anglophile)
Jay is three times as old as Greg. Six years ago, the sum of their ages is equal to... (answered by Nigelyul)
A man is now five times as old as his daughter and five years ago the product of their... (answered by ikleyn)
C's age is 6 more than the sum of the ages of A and B. Five years from now A will be half (answered by ankor@dixie-net.com)
A man is five times as old as his daughter. six years ago,the product of their age was... (answered by josmiceli)