SOLUTION: yato is twice as old as his brother yukine. the quotient of their ages five years ago was seven less than yukine’s present age. Find their present ages.
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Question 1169566: yato is twice as old as his brother yukine. the quotient of their ages five years ago was seven less than yukine’s present age. Find their present ages.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Yato, 2b
Brother Yukine, b
Second sentence,
.
.
.
.
The one which works: b=4
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R E T R Y
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Returning to quadratic,
Factorize,
Possible solutions to check, b=4 or b=10.
Using the quotient description
b if 4
arithmetic works but either age five years ago must not be negative.
b if 10
-
b=4 will not work.
b=10 will work.
Answer by ikleyn(52786) (Show Source): You can put this solution on YOUR website!
.
My post is the CORRECTION to the answer by @josgarithetic.
The correct answer is :
the present ages are 10 years (the brother) and 20 years (Yato).
The answer b= 4 for the brother, given by @josgarithmetic, is INCORRECT and does not work.
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