SOLUTION: Kevin is now four times as old as mark. Five years ago, The sum of their ages was 45. How old are they now? (Hint:k=44)

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Question 1169117: Kevin is now four times as old as mark. Five years ago,
The sum of their ages was 45. How old are they now? (Hint:k=44)
Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

let Kevin's age be and Mark's age
given:
Kevin is four times as old as Mark:
....eq.1
Five years ago, Kevin was years old and Mark was
and, the sum of their ages was : so we have




........solve for
.....eq.2
from eq.1 and eq.2 we have





go to:
....eq.1, substitute


so, Kevin is and Mark is


Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Kevin is now four times as old as mark. Five years ago,
The sum of their ages was 45. How old are they now? (Hint:k=44)
Let Mark's age be M

Then Kevin's is: 4M

We then get: M + 4M - 2(5) = 45

5M = 55

Mark, or 

Now you can find Kevin's age! 

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