SOLUTION: The sum of the ages of two sisters, Mary and Jane, is 24 years. Four years ago three times Mary’s age was 3 years more than twice Jane’s age. Determine their current ages.

Question 1168878: The sum of the ages of two sisters, Mary and Jane, is 24 years. Four years ago three times Mary’s age was 3 years more than twice Jane’s age. Determine their current ages.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!

substitute,

------MISTAKE FOUND HERE

-------------~~maybe. Only if you could expect the year cut into twelfths or into quarters.~~

Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

The sum of the ages of two sisters, Mary and Jane, is 24 years. Four years ago three times Mary’s age was 3 years more than twice Jane’s age. Determine their current ages.

Don't believe what he tells you! Mary's age is NOT a MIXED number, so .
In fact,
You can do the CHECK!!
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