SOLUTION: (x-4)(x+5)≤0/(x+2)(x²+3)

Algebra.Com
Question 1164816: (x-4)(x+5)≤0/(x+2)(x²+3)
Found 2 solutions by Edwin McCravy, greenestamps:
Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
(x-4)(x+5)≤0/(x+2)(x²+3)
"To divide an inequality by an expression" doesn't make any sense.

Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!


Pay attention to what you have written before you post it.

(1) Your "<=0" is in the wrong place
(2) Required parentheses are missing

And, most importantly,

(3) You didn't ask a question

Presumably this is what you meant:

((x-4)(x+5))/((x+2)(x^2+3))<=0



I could go ahead and answer what your probable question is....

But instead I ask you to re-post, showing the inequality correctly AND asking your question.


RELATED QUESTIONS

(x-1)(x-2)(x-3)<0... (answered by lwsshak3)
1.(x+7)(x+1)=0 2.(x+2)(x+3)=0 3.x(x-2)=0 4.x(x-7)=0... (answered by MathLover1)
how do i solve this problem?... (answered by longjonsilver)
(x+3)/(x+2)-(x+4)/(x+3)=(x+5)/(x+4)-(x+6)/(x+5) (answered by Tatiana_Stebko)
3*x^2-5*x-2=0 (answered by MathLover1)
7(x - 4) -5(x+ 2) =... (answered by MathLover1)
{{{((((x)^0)^2)^4)^5)}}} (answered by solver91311)
x^4 - x^3 + x^2 - x + 1 =... (answered by ikleyn)
4(x - 3) - 2(x - 1) >... (answered by checkley71)