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Faith is 10 years older than Grace. Eight years ago, Faith was 3 times Grace's age. How old are they now?
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Let x be the Grace age; Then Faith is (x+10) years old.
Eight years ago they were (x-8) (Grace) and ((x+10)-8) = (x+2) (Faight) years old.
The condition says
x+2 = 3*(x-8).
From this equation
x+2 = 3x - 24
2 + 24 = 3x - x
26 = 2x
x = 26/2 = 13.
ANSWER. Grace is 13 years old; Faith is 13+10 = 23 years old.
CHECK. 8 years age they were 13-8 = 5 and 23-8 = 15 years old with the ratio = 3. ! Correct !
Solved.
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There is a bunch of lessons on age word problems
- Age problems and their solutions
- A fresh formulation of a traditional age problem
- Really intricate age word problems
- Selected age word problems from the archive
- Age problems for mental solution
- Miscellaneous age problems
in this site.
Read them and become an expert in solving age problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Age word problems".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.