SOLUTION: In a round robin competition, everyone plays everyone else at least once. How many games would be played if there were six players? How many more games would be needed if three e

Algebra.Com
Question 1163013: In a round robin competition, everyone plays everyone else at least once. How
many games would be played if there were six players? How many more games
would be needed if three extra players entered the competition?
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.

To be correct, the problem should be formulated in DIFFERENT WAY: 

    In a round robin competition, everyone plays everyone else  exactly one time. 
    How many games would be played if there were six players? 

    How many more games would be needed if three extra players entered the competition?


Then the answer to the first question is    = 3*5 = 15  games.


The answer to the second question is    - 15 = 9*4 - 15 = 36 - 15 = 21  games   (the difference).

Solved.

------------------

For n participants, the number of games between them is   .



RELATED QUESTIONS

if 109 boys play a chess tournament, how many games have to be played so that each boy... (answered by htmentor)
In a round tournament every team plays every other team once. Example: For a three teams (answered by stanbon)
Kathy had a party. Everyone at the party shook hands with everyone else. How many... (answered by askmemath)
fifteen people are at a party. if each person shakes hands with everyone else(just... (answered by KMST)
6 teams are involved in a round robin tournament. In a tournament, each team plays every... (answered by ewatrrr)
at a family gift exchange everyone gave everyone else one gift. If there were a total of... (answered by MathTherapy)
In a 9 team league where everyone plays each other once, I figured there would be 36... (answered by richwmiller)
In a basketball league of x teams of which every team plays every other twice, the total... (answered by ikleyn)
In a​ round-robin chess​ tournament, each player is paired with every other... (answered by jim_thompson5910,ikleyn)