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Sandy is twice as old as Candy, and Dandy is nine years older than Candy.
Three years ago, Sandy was nine less than three times Candy's age. How old was Dandy 3 years ago?
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Let x be the Candy's age.
Then the Sandy's age is 2x years.
Three years ago
Sandy was 2x-3 years old, and
Candy was (x-3) years old.
The condition says that
2x-3 = 3(x-3) - 9 ("Three years ago, sandy was nine less than three times candy's age")
Simplify and solve
2x - 3 = 3x - 18
18 - 3 = 3x - 2x
x = 15.
Thus the Candy's age is 15 years now.
Dandy is nine years older than Candy, so Dandy is 15+9 = 24 years old now.
3 years ago, Dandy was 24-3 = 21 years old. ANSWER
Solved.
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There is a bunch of lessons on age word problems
- Age problems and their solutions
- A fresh formulation of a traditional age problem
- Really intricate age word problems
- Selected age word problems from the archive
- Age problems for mental solution
- Miscellaneous age problems
in this site.
Read them and become an expert in solving age problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Age word problems".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.
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