Let (x,y) be the current point on the perpendicular bisector. Its distance from the point (4,3) is. Its distance from the point (-2,5) is . The distances are equal = . Square both sides (x-4)^2 + (y-3)^2 = (x+2)^2 + (y-5)^2. Simplify x^2 - 8x + 16 + y^2 - 6y + 9 = x^2 + 4x + 4 + y^2 - 10y + 25 -8x - 4x + (-6y + 10y) = 4 + 25 - 16 - 9 -12x + 4y = 4 3x - y = -1. ANSWER