Let x be the present age of the daughter. Then the present age of the mother is 4*(x-4)+4 = 4x - 12. From the condition, you have this equation x*(4x-12) = 432. Cancel the factor 4 in both sides x*(x-3) = 108. You can solve this quadratic equation. An alternative way is to decompose MENTALLY the number 108 into the product of two factors with the difference 3 between them 108 = 9*12, so the answer is the greater of these two factors x= 12. ANSWER. The daughter is 12 years old. The mother is 4x - 12 = 4*12-12 = 36 years old. CHECK. 12*36 = 432. ! Correct !
Let mother's and daughter's ages be M and D, respectively
Then we get: MD = 432 ------ eq (i)
Also, M - 4 = 4(D - 4)____M - 4 = 4D - 16_____M = 4D - 12 ----- eq (ii)
D(4D - 12) = 432 ------ Substituting 4D - 12 for M in eq (i)
(D - 12)(D + 9) = 0
Daughter's age, orOR D = - 9 (ignore)