# SOLUTION: My mom even tried to work this problem out. My teacher got it from edHelper.com. 1. In ten years, Eric's age will be seventy-three less than four times the age of Alexander. 2.

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: My mom even tried to work this problem out. My teacher got it from edHelper.com. 1. In ten years, Eric's age will be seventy-three less than four times the age of Alexander. 2.       Log On

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 Question 115629: My mom even tried to work this problem out. My teacher got it from edHelper.com. 1. In ten years, Eric's age will be seventy-three less than four times the age of Alexander. 2. Kevin is sixty-three years younger than Jonathan. 3. Elizabeth is forty-one years older than Kevin. 4. The sum of of the ages of Elizabeth and Kevin is sixty-seven. 5. Eric's age is sixteen less than three times the age of Alexander. This is how far my mom and I got on this question: 1. 4a - 73 a=Alexander 2. e - 63 b=Eric 3. d + 41 c=Elizabeth 4. c + d = 67 d=Kevin 5. 3a - 16 e=Jonathan 3. 41 + 34 = 75 4. 34 + 33 = 67 My mom and I would appreciate any help with this problem. Thank you for taking the time out to help us.Answer by stanbon(60774)   (Show Source): You can put this solution on YOUR website!1. In ten years, Eric's age will be seventy-three less than four times the age of Alexander. (E+10) = 4(A+10) - 73 -------------------- 2. Kevin is sixty-three years younger than Jonathan. K = J - 63 -------------------- 3. Elizabeth is forty-one years older than Kevin. E = K + 41 -------------------- 4. The sum of of the ages of Elizabeth and Kevin is sixty-seven. E + K = 67 ------------------- 5. Eric's age is sixteen less than three times the age of Alexander. E = 3A - 16 ------------------- #3: E-K=41 #4: E+K=67 Add to get:2E = 108 E = 54 years old K = 13 years old ------------------ #5: E =3A-16 But E = 54 54 = 3A-16 3A = 70 A = 70/3 years old ---------------------------- #1: (E+10) = 4(A+10) - 73 (54+10) = 4A+40 - 73 64 = 4A+40 - 73 4A = 97 A = 97/4 Comment: Result contradicts A = 70/3 ================== Cheers, Stan H.