SOLUTION: The sum of leahs age and Andy’s age is 34. Five years ago the sum of twice leahs age and three times Andy’s age was 61 How old are they now?
Question 1152883: The sum of leahs age and Andy’s age is 34. Five years ago the sum of twice leahs age and three times Andy’s age was 61 How old are they now? Found 2 solutions by MathLover1, MathTherapy:Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
let Leah's age be and Andy’s age
if the sum of Leah's age and Andy’s age is we have
......eq.1
if years ago the sum of Leah's age and Andy’s age was , we have
......eq.2
solve the system:
......eq.1......both sides multiply by ......eq.2
------------------------------------
......eq.1. ......eq.2
-------------------------------add both eq.
go to
......eq.1, substitute
How old are they now?
Leah is years old now, and Andy is years old now
Let Andy's age be A
Then Leah's is: 34 - A
We then get: 3(A - 5) + 2(34 - A - 5) = 61
3A - 15 + 2(29 - A) = 61
3A - 15 + 58 - 2A = 61
That's IT!! No COMPLEXITIES!