SOLUTION: A man's age is 6 less than three times his son's age.the sum of their age is 58.how old is the man's age?

Question 1151474: A man's age is 6 less than three times his son's age.the sum of their age is 58.how old is the man's age?
Found 3 solutions by MathLover1, MathTherapy, greenestamps:
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

let man's age be and his son's age
if a man's age is less than his son's age. we have
.........eq.1

if the sum of their age is , we have
........eq.2

substitute from eq.1
........eq.2.....solve for

now calculate

.........eq.1

the man is years old

Answer by MathTherapy(10557)   (Show Source): You can put this solution on YOUR website!

A man's age is 6 less than three times his son's age.the sum of their age is 58.how old is the man's age?

Let man's age be M, and son's, S
Then we get: M = 3S - 6 ------- eq (i)
Also, M + S = 58____S = 58 - M ------ eq (ii)
M = 3(58 - M) - 6 ------ Substituting 58 - M for S in eq (i)
M = 174 - 3M - 6
4M = 168
M, or
Answer by greenestamps(13214)   (Show Source): You can put this solution on YOUR website!

The path to the solution is easier if you use a single variable....

x = son's age
3x-6 = man's age

The sum of their ages is 58:

The son's age is x=16
The man's age is 3x-6 = 48-6 = 42

By the way....

"how old is the man?" okay....
"what is the man's age?" okay....
"how old is the man's age?" not English....

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