SOLUTION: The sum of the ages of even and Diane is 60 years. 12 years ago, Evans age was 2 times dianas. How old is even now?

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Question 1151245: The sum of the ages of even and Diane is 60 years. 12 years ago, Evans age was 2 times dianas. How old is even now?
Found 3 solutions by MathLover1, ikleyn, MathTherapy:
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

let Evan's age be and Diana's age
if the sum of the ages of Even and Diane is years, we have
......eq.1
if years ago, Evan's age was times Diana's,we have
..........solve for


......eq.2

go to eq.1, substitute from eq.2

........solve for





go back to
......eq.2, substitute




so, Even is years old now


Answer by ikleyn(52794)   (Show Source): You can put this solution on YOUR website!
.

            You can solve this problem using simple Algebra with one single equation.


Let X be the Diana's age 12 years ago.

Then the Evan's age 12 years ago was 2x years, according to the condition.


Their present ages are (x+12) and (2x+12), and the sum of their present ages is 


    (x+12) + (2x + 12) = 60.


Simplify and solve this equation


    3x + 24 = 60,

    3x = 60 - 24

    3x = 36

     x = 36/3 = 12.


So, Dianas's age 12 years ago was 12 years; Evans age 12 years ago was 24 years.

Hence, Evan's age now is 24+12 = 36 years.   ANSWER


            You can also solve this problem mentally, without using equation/equations.


12 years ago, Evans age was 2 times Diana's age, and the sum of their ages at that time was 60-12-12 = 36 years.


Hence, the Diana's age 12 years ago was    of 36 years, i.e. 12 years.


Then Evean's age at that time was 24 years, and now Evance age is 24+12 = 36 years.    (the same answer)

-----------------

There is a bunch of lessons on age word problems
    - Age problems and their solutions
    - A fresh formulation of a traditional age problem
    - Really intricate age word problems
    - Selected age word problems from the archive
    - Age problems for mental solution
in this site.

Read them and become an expert in solving age problems.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Age word problems".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.


Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

The sum of the ages of even and Diane is 60 years. 12 years ago, Evans age was 2 times dianas. How old is even now?
Let Evan's age be E
Then Diane's is: 60 - E
Then 12 years ago, we had: E - 12 = 2(60 - E - 12)
E - 12 = 2(48 - E)
E - 12 = 96 - 2E
E + 2E = 96 + 12
3E = 108
Evan's age, or
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