SOLUTION: Dyke is 27 years old than his daughter. In 10 years he will be twice as old as his daughter. How old they are now? Please help me.

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Question 1151139: Dyke is 27 years old than his daughter. In 10 years he will be twice as old as his daughter. How old they are now?
Please help me.
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52802)   (Show Source): You can put this solution on YOUR website!
.
Dyke is 27 years older than his daughter.
In 10 years he will be twice as old as his daughter. How old they are now?
~~~~~~~~~~~~~~~~ 


Let x be the daughter's age.

Then his father's age is (x+27) years.


In 10 years,


    the daughter's age will be (x+10) years, while

    the father's age will be (x+27+10) = (x+37) years.


You are given

    x+37 = 2*(x+10).


It is your basic equation.

As soon as you got it, you just solved the problem in half.


To solve it COMPLETELY, simplify your equation step by step


    x + 37 = 2x + 20

    37 - 20 = 2x - x

    17      = x.


ANSWER.  The daughter is 17 years old.  The father is 27 years older, i.e. 17+27 = 44 years old.

Solved.

Now  YOU  check it  ON  YOUR  OWN  that all conditions of the problem are satisfied.

-------------------

There is a bunch of lessons on age word problems
    - Age problems and their solutions
    - A fresh formulation of a traditional age problem
    - Really intricate age word problems
    - Selected age word problems from the archive
    - Age problems for mental solution
in this site.

Read them and become an expert in solving age problems.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Age word problems".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.


Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!


(1) Algebraically....

Let x be his daughter's age; then x+27 is his age.

In 10 years his daughter's age will be x+10 and his age will be x+37.

At that time his age will be twice his daughter's age:



Solve using basic algebra....

(2) Using simple logical reasoning....

The difference in their ages is 27 years.

So when he is twice as old as his daughter, their ages will be 27 and 54.

Since that will be 10 years from now, their current ages are 17 and 44.
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