SOLUTION: Isabelle is 5 years older than her brother joseph ,in 15years the sum of their age is 65. Find their present age

Question 1150918: Isabelle is 5 years older than her brother joseph ,in 15years the sum of their age is 65. Find their present age
Found 2 solutions by math_helper, Alan3354:
Answer by math_helper(2461) (Show Source): You can put this solution on YOUR website!
Let n = Isabelle's age

(n+15) + (n-5+15) = 65

Solve for n (Isabelle's age) then n-5 is Joseph's age.

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Isabelle is 5 years older than her brother joseph. In 15years the sum of their age is 65. Find their present age
======================
in 15 years the sum of their ages is 65 ---> sum now is 35
---
I + J = 35
I - J = 5
------------------- Add
2I = 40
I = 20
J = 15

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