SOLUTION: The ratio of David's age 5years ago and in 8 years time is 2:3. How old was David 11years ago

Question 1148230: The ratio of David's age 5years ago and in 8 years time is 2:3. How old was David 11years ago
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52786) (Show Source): You can put this solution on YOUR website!
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Let x be the David's age. From the condition, you have this equation = . To solve it, cross multiply; then simplify 3*(x-5) = 2*(x+8) 3x - 15 = 2x + 16 3x - 2x = 16 + 15 x = 31 is the current David's age. ANSWER

Solved.

Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

The difference between 5 years ago and 8 years from now is 13 years.

If the ratio of his ages at those two times is 2:3, then those two ages are 2*13=26 and 3*13 = 39.

So 5 years ago David was 26; that means 11 years ago he was 20.

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