.
I will try to provide more short solution.
Let x be the Matt's age. Then James' age is 90-x years.
When Matt will be twice as old as James is now ?
- In 2*(90-x)-x years, which is 180-3x years.
What will be the James' age in 180-3x years ?
- James age will be (90-x) + (180-3x), or, after simplifying, (270-4x) years.
Then the condition says
x =
It is your basic equation to the problem. Now your task is to solve it.
2x = 270 - 4x
6x = 270
x = 270/6 = 45.
ANSWER. Matt is 45 years old. James is 90-45 = 45 years old, too.
CHECK. When Matt will be twice as old as James is now (i.e. as old as 2*45 = 90 years ?
- In 90-45 = 45 years.
What will be James' age in 45 years ?
- it will be 45 + 45 = 90.
45 = . ! Correct !
Solved.
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In such problems, than shorter, compact and straightforward the solution is, than more (and better) it is understandable.
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In this site, there is a bunch of age word problems
- Age problems and their solutions
- A fresh formulation of a traditional age problem
- Really intricate age word problem (*)
- Selected age word problems from the archive
- Age problems for mental solution
- One unusual age word problem
- Age problems with a defective sum of ages
- OVERVIEW of lessons on age problems
Of them, the problem marked (*) in the list is very close to the given problem.
Read the lessons and become an expert in solving age problems (!)
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Age word problems".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.