SOLUTION: Jane is 4 years old then Paul. The sum of three times janes age and two times Paul’s age is 67. How old are Jane and Paul?

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Question 1147014: Jane is 4 years old then Paul. The sum of three times janes age and two times Paul’s age is 67. How old are Jane and Paul?
Found 2 solutions by ikleyn, richwmiller:
Answer by ikleyn(52786)   (Show Source): You can put this solution on YOUR website!
.
Jane is 4 years older than Paul.
The sum of three times janes age and two times Paul’s age is 67. How old are Jane and Paul?
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Let x be the Jane age;  then the Paul's age is (x-4) years.


From the condition, you have this equation


    3x + 2*(x-4) = 67.


Solve it for x, the Jane's age.


Then evaluate (x-4), the Paul's age.


Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
There are several problems with the English in the first sentence!
Can't you copy the problems correctly?

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