SOLUTION: Mother is four times old as Mary. Five years ago, she was seven times as old. How old will each be in five years?

Question 1134466: Mother is four times old as Mary. Five years ago, she was seven times as old. How old will each be in five years?
Answer by mathsolverplus(88) (Show Source): You can put this solution on YOUR website!
Mother's age = x
Mary's age = y
Present: x = 4y Mother is four times old as Mary
Past: x-5 = 7(y-5) Both age needs to be subtracted from five first.
4y-5=7y-35
-3y=-30
y=10
x=40 and y=10
Mother's age in five years = 40+5 =45 years old
Mary's age in five years = 10+5 = 15 years old

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