SOLUTION: Jessa is 15 years older than her student.In 15 years, twice her age will be thrice the age of her student.Find the present age of her student.

Question 1132480: Jessa is 15 years older than her student.In 15 years, twice her age will be thrice the age of her student.Find the present age of her student.
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52800)   (Show Source): You can put this solution on YOUR website!
.

Let x be the present age of her student. Then Jessa's present age is (x+15) years. In 15 years . . . 2*((x+15) + 15) = 3*(x+15). It is your basic equation. Simplify and solve it step by step 2x + 60 = 3x + 45 60 - 45 = 3x - 2x ====> x = 15. <<<---=== the student's present age. ANSWER CHECK. Then Jessa's present age is 15 + 15 = 30 years. ("Jessa is 15 years older than her student.") In 15 years: Jessa is 45 years old; the student is 15 + 15 = 30 years old. 2*45 = 90 = 3*30. ! Precisely correct !

Solved.     Congrats ! !

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Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!

(1) The difference in their ages will always be 15 years.

(2) In 15 years, twice her age will be thrice the age of her student. In other words, her age will be 3/2 of her student's age.

(3) 3/2 her student's age, with an age difference of 15 years, will be when she is 45 and her student is 30.

(4) Since that will be 15 years from now, she is now 30 and her student is now 15.
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