SOLUTION: Elizabeth is twice as old as cathrine. If seven years ago the sum of their ages was 82, how old are they now?
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Question 1131176: Elizabeth is twice as old as cathrine. If seven years ago the sum of their ages was 82, how old are they now?
Found 2 solutions by htmentor, MathLover1:
Answer by htmentor(1343) (Show Source): You can put this solution on YOUR website!
Let E = Elizabeth's age, C = Cathrine's age
Elizabeth is twice as old as Cathrine:
E = 2C
Seven years ago their ages were E - 7 and C - 7 and their sum was 82:
E - 7 + C - 7 = 82
Substitute for E from the 1st equation:
2C - 7 + C - 7 = 82
3C = 96
C = 32
Thus Cathrine is 32 and Elizabeth is 64
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
let Elizabeth's age be and Catherine's age be
if Elizabeth is twice as old as Catherine, we have
.........eq.1
seven years ago:
.....Elizabeth's age
......Catherine's age
If seven years ago the sum of their ages was , we have
..-> substitute from eq.1
find
.........eq.1
how old are they now: Elizabeth is and Catherine is
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