SOLUTION: sally has money in two accounts. one account pays 5% interest, whereas the other pays 11% annual interest. if she has $400 more invested at 11% than she does at 5% and her total in

Question 1129933: sally has money in two accounts. one account pays 5% interest, whereas the other pays 11% annual interest. if she has $400 more invested at 11% than she does at 5% and her total interest for a year is $172, how much does she have in each account?
Answer by ikleyn(52796) (Show Source): You can put this solution on YOUR website!
.

Let x be the amount invested at 11%, in dollars.


Then the amount invested at 5% is (x-400) dollars.


The condition says


    interest + interest     = total interest,  or


    0.11x    + 0.05*(x-400) = 172
   

    0.11x + 0.05x - 0.05*400 = 172

    0.16x = 172 + 0.05*400

    x =  = 1200 dollars.


Answer.  1200 invested at  11%,  and  1200 - 400 = 800 dollars invested at 5%.


Check.  0.11*1200 + 0.05*800 = 172 dollars.   ! Correct !

Solved.

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