SOLUTION: John's age is 3 times more than twice his younger brother's age. If the sum of their ages is at most 18, write an equation to express possible ages for John.
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Question 1128059: John's age is 3 times more than twice his younger brother's age. If the sum of their ages is at most 18, write an equation to express possible ages for John.
This is a question my Algebra 1 teacher has given me, I've tried every equation that I have thought of and every time she's told me I'm wrong. Please help
Found 2 solutions by MathLover1, htmentor:
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
let's John's age be and his brother's age be
if John's age is times than his younger brother's age, we have (I guess it's more, not times)
...eq.1
If the sum of their ages is , write an equation to express possible ages for John,
....eq.2 ...(since given )
now you can substitute from eq.1 in eq.2 and solve for
-> his brother's age is
now go to ...eq.1 and find John's age
...eq.1
->John's age
Answer by htmentor(1343) (Show Source): You can put this solution on YOUR website!
I assume you mean 3 more than twice his brother's age instead of 3 times more.
Let x = the younger brother's age, y = John's age
y = 3 + 2x -> x = y/2 - 3/2
x + y <= 18 y <= 18 - x -> y <= 18 - y/2 + 3/2
Solve the inequality for y:
3y/2 <= 39/2
y <= 13
So John's age is less than or equal to 13
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