SOLUTION: Ann's age is seven tenths of Bill's age. In 4 years Ann's age will be eight elevenths of Bills age. How old is Bill now? I can't get this. Thanks for your help

Question 111971: Ann's age is seven tenths of Bill's age. In 4 years Ann's age will be eight elevenths of Bills age. How old is Bill now?
I can't get this. Thanks for your help
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
A=.7B
IN 4 YEARS THEIR AGES WILL BE:
AMY=.7B+4
AND BILL WILL BE B+4
.7B+4=(B+4)8/11
.7B+4=(8B+32)/11 NOW CROSS MULTIPLY
11(.7B+4)=8B+32
7.7B+44=8B+32
7.7B-8B=32-44
-.3B=-12
B=-12/.3
B=40 YEARS OLD NOW.
A=.7*40
A=28 YEARS OLD NOW.
PROOF
28+4=(40+4)8/11
32=44*8/11 (DIVIDE 44 BY 11)
32=4*8
32=32

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