SOLUTION: NINE YEARS AGO, MICHAEL IS FIVE TIMES OLD AS TOM. NOW, HE IS ONLY THREE TIMES AS OLD AS TOM. FIND THEIR PRESENT AGES.

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Question 1117562: NINE YEARS AGO, MICHAEL IS FIVE TIMES OLD AS TOM. NOW, HE IS ONLY THREE TIMES AS OLD AS TOM. FIND THEIR PRESENT AGES.
Answer by ikleyn(52814)   (Show Source): You can put this solution on YOUR website!
.
Let T be the Tom's current age.

Then the Michael current age is 3T.


9 years ago Tom was (T-9) years old, while Michael was 3T-9 years old, and for that time

3T -9 = 5*(T-9),   according to the condition.


Simplify and solve for T:


3T - 9 = 5T - 45

45 - 9 = 5T - 3T

36 = 2T  ====>  T =  = 18.


Answer.  Tom is 18 years old;  Michael is 3*18 = 54 years old.


         Nine years ago:  T = 9;  M = 45;  The ratio is   = 5  ----> the solution is correct !

Solved.

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There is a bunch of lessons on age word problems
    - Age problems and their solutions
    - A fresh formulation of a traditional age problem
    - Really intricate age word problem
    - Selected age word problems from the archive
    - Age problems for mental solution
in this site.

Read them and become an expert in solving age problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Age word problems".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.

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