SOLUTION: Jill is 2 times as old as Amanda. The sum of their ages 7 years ago was 13. How old are they now?
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Question 1116969: Jill is 2 times as old as Amanda. The sum of their ages 7 years ago was 13. How old are they now?
Found 2 solutions by jim_thompson5910, josgarithmetic:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
J = Jill's current age
A = Amanda's current age
J = 2*A because "Jill is 2 times as old as Amanda"
Seven years ago, Jill was J-7 years old and Amanda was A-7 years old. The sum of their ages back then was 13, so,
(J-7)+(A-7) = 13
J+A-14 = 13
J+A-14+14 = 13+14
J+A = 27
Plug in J = 2A and solve for A
J+A = 27
2A+A = 27
3A = 27
A = 27/3
A = 9
Use this to find J
J = 2*A
J = 2*9
J = 18
Jill is 18 years old currently. Amanda is 9 years old currently.
As a check, if we go back 7 years then Jill is now 11 years old while Amanda is 2 years old. Their past ages sum to 11+2 = 13.
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
Jill, 18
Amanda, 9
--------Amanda
-
------Jill
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