SOLUTION: right now, Connie is twice as old as her brother. Six years ago, she was 4 times his age. How old are they now?

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Question 1115642: right now, Connie is twice as old as her brother. Six years ago, she was 4 times his age. How old are they now?
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
C = 2*B           (1)   (right now)

C-6 = 4*(B-6)     (2)   (six years ago . . . )


Substitute (1) into eq(2) to get


2B - 6 = 4*(B-6),

2B - 6 = 4B - 24

24 - 6 = 4B - 2B

18 = 2B  ====>  B =  = 9.


Answer.  The brother is 9 years now.   Connie age is 18 years.

Solved.

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There is a bunch of lessons on age word problems
    - Age problems and their solutions
    - A fresh formulation of a traditional age problem
    - Really intricate age word problem
    - Selected age word problems from the archive
    - Age problems for mental solution
in this site.

Read them and become an expert in solving age problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Age word problems".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

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