SOLUTION: Lucas is 9 years older than three times his son's age. In 5 years, the age of Lucas will be 6 years more than twice his son's age. Find their present age.

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Question 1110899: Lucas is 9 years older than three times his son's age. In 5 years, the age of Lucas will be 6 years more than twice his son's age. Find their present age.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
L, Lucas
c, Lucas'es son

This is the literal translation into equations:


Solve the system for L and c.

Answer by ikleyn(52787)   (Show Source): You can put this solution on YOUR website!
.
L = 9 + 3*S,             (1)

L + 5 = 6 + 2*(S+5).     (2)



Substitute (1) into (2).  You will get

9 + 3*S + 5 = 6 + 2S + 10,

S = 6 + 10 - 9 - 5 = 2.


Thus we found that the son is 2 years old.

Then Lucas (= the father of his son) is 9 + 3*2 = 9 + 6 = 15 years old.

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