SOLUTION: Mary is twice as old as Judy. Six years ago Mary was three times as old as Judy. Find the age of each perso now.

Question 1106923: Mary is twice as old as Judy. Six years ago Mary was three times as old as Judy. Find the age of each perso now.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
m = Mary's present age
j = Judy's
:
Mary is twice as old as Judy.
m = 2j
Six years ago Mary was three times as old as Judy.
m-6 = 3(j-6)
m - 6 = 3j - 18
m = 3j - 18 + 6
m = 3j - 12
Find the age of each person now.
Replace m with 2j
2j = 3j - 12
2j - 3j = -12
-j = -12
j = 12 yrs is Judy's names
therefore
2(12) = 24 yrs is Mary's name
:
:
:
Check this in the statement "Six years ago Mary was three times as old as Judy."
24 - 6 = 3(12-6)
18 = 3(6)

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