SOLUTION: When Lucy married 18 yrs ago her husband to be was three times her age, and today he's twice her age, how old was she when she married him?

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Question 1104505: When Lucy married 18 yrs ago her husband to be was three times her age, and today he's twice her age, how old was she when she married him?
Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!
L = Lucy's age now
L-18 = Lucy's age 18 years ago
H = Husband's age now
H-18 = Husband's age 18 years ago.

When Lucy married 18 yrs ago her husband to be was three times her age
 H-18 = 3(L-18)

and today he's twice her age,
    H = 2L
Substitute 2L for H in
 H-18 = 3(L-18)
2L-18 = 3(L-18)
2L-18 = 3L-54
   -L = -36
    L = 36

H = 2L
H = 2(36)
H = 72

how old was she when she married him?
 L-18 = Lucy's age 18 years ago (when she married)
36-18 = 18

Lucy was 18 when she married and was very foolish 
at 18 to marry a man 54, don't you think?

Edwin


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