SOLUTION: There are 5 children in the Yoshida Family. The youngest is in the third grade. The oldest is twice as old as the youngest. The Triplets are 4 years younger than the oldest. the p

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Question 1101480: There are 5 children in the Yoshida Family. The youngest is in the third grade. The oldest is twice as old as the youngest. The Triplets are 4 years younger than the oldest. the product of all the childeren's age is 221,184. how old each child?

Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39623)   (Show Source): You can put this solution on YOUR website!
Grade level and age are not the same thing but are related and depend on where a person lives. If grade 0 (kindergarten) is age 5, then grade 3 would be age 8. 
Children             Age (possibly)

youngest               8

3 in the triplet      16-4=12

oldest                16

Product of all five of these ages: ------perfect match to description.
Answer by greenestamps(13203)   (Show Source): You can put this solution on YOUR website!


Let x be the age of the triplets; then the ages of the oldest and youngest are x+4 and x-4.

So the product of all the ages is .

That product is very close to x^5; so use a calculator or do some estimation to find a value of x for which x^5 is close to 221,184.

approximately; so x should be 12.

Now check:
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