SOLUTION: Jack is 2 times as old as Lacy. 7 years from now the sum of their ages will be 59.How old are they now?

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Question 1099090: Jack is 2 times as old as Lacy. 7 years from now the sum of their ages will be
59.How old are they now?

Found 2 solutions by josmiceli, MathTherapy:
Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
Let = Jack's age now
Let = Lacy's age now
----------------------------
(1)
(2)
-----------------------------
Plug (1) into (2)
(2)
(2)
(2)
(2)
and
(1)
(1)
-------------------
Jack is 30 and
Lacy is 15
-------------------
check:




OK

Answer by MathTherapy(10555)   (Show Source): You can put this solution on YOUR website!

Jack is 2 times as old as Lacy. 7 years from now the sum of their ages will be
59.How old are they now?
Seven years from now the sum of their ages will be 59, so currently, the sum of their ages is 59 - 2(7), or 59 - 14 = 45
With Lacy's age being L, Jack's is: 2L
We then get: L + 2L = 45
3L = 45

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