SOLUTION: Tom is twice as old as Andy. In 4 years time the sum of the ages will be 32 years. Find Andy’s present age.

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Question 1097474: Tom is twice as old as Andy. In 4 years time the sum of the ages will be 32 years. Find Andy’s present age.
Found 2 solutions by amalm06, MathTherapy:
Answer by amalm06(224)   (Show Source): You can put this solution on YOUR website!
Let T=Tom's Age, A=Andy's Age
Then T=2A and (T+4)+(T/2)+4=32
So that (3/2)T+8=32 --> (3/2)T=24 --> T=48/3=16
Therefore, A=16/2=8 (Answer)
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Tom is twice as old as Andy. In 4 years time the sum of the ages will be 32 years. Find Andy’s present age.
In 4 years, their ages sum to 32, so now, their ages sum to 32 - 2(4), or 32 - 8 = 24

Let Andy's be A

Then Tom's is 2A

We then get: A + 2A = 24

3A = 24

Andy, or  

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