Teresa's AGE is good enough. Current is UNNECESSARY, as explained by Alan.

FYI: Teresa can NEVER be 22, as suggested by "you know who," so as usual, IGNORE, IGNORE, IGNORE! 

Answer by ikleyn(52802)   (Show Source): You can put this solution on YOUR website!
 .

Solution 1





Directly from the condition, you have this system of 2 equations in 2 unknowns:


T - A = 6             (1)    ("Teresa is 6 years older than Ann.")
(T+4) + (A+4) = 66    (2)    ("In 4 years")


Simplify:

T - A =  6,           (1')
T + A = 58.           (2')


Add the equations 1') and (2')  (both sides).   You will get

2T = 6+58 = 64  ====>  T =  = 32.


Answer.  Teresa is 32 years old.




Solution 2





A = T - 6,

(T+4) + (A+4) = 66.


Replace A in the last equation by (T-6) based on the previous equation. You will get

(T+4) + ((T-6)+4) = 66.


You have a single equation for unknown T. Simplify and solve for T.


T + 4 + T - 6 + 4 = 66  ====>

2T + 2 = 66  ====>  2T = 66-2 = 64  ====>  T =  = 32.


You got the same answer.




----------------

There is a bunch of lessons on age word problems 



    - Age problems and their solutions



    - A fresh formulation of a traditional age problem



    - Really intricate age word problem



    - Selected age word problems from the archive



    - Age problems for mental solution 



in this site.





Read them and become an expert in solving age problems.





Also, you have this free of charge online textbook in ALGEBRA-I in this site



    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.





The referred lessons are the part of this online textbook under the topic "Age word problems".







Save the link to this online textbook together with its description





Free of charge online textbook in ALGEBRA-I

https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson





to your archive and use it when it is needed.







 

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