SOLUTION: A mother is presently four times as old as her daughter. The sum of their ages six years ago was 48. Find each persons current age.

Question 1095311: A mother is presently four times as old as her daughter. The sum of their ages six years ago was 48. Find each persons current age.

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A mother is presently four times as old as her daughter. The sum of their ages six years ago was 48. Find each persons [sic] current age.
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"presently" and "current" are superfluous.
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A mother is four times as old as her daughter. The sum of their ages six years ago was 48. Find each person's age.
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The sum of their ages six years ago was 48 --> the sum is now 60.
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M = 4D
M + D = 60
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Sub for M
4D + D = 60
D = 12
M = 48

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