SOLUTION: Maria is four times older than Marty. The sum of their age is 55 years. How old are they?

Algebra.Com
Question 1095015: Maria is four times older than Marty. The sum of their age is 55 years. How old are they?
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Maria is four times older than Marty. The sum of their age is 55 years. How old are they?
-----------
1 time older --> 100% older = 2 times as old.
2 times older --> 200% older = 3 times as old.
3 times older --> 300% older = 4 times as old.
4 times older --> 400% older = 5 times as old.
=================
Maria = 5*Marty
Maria + Marty = 55
Sub for Maria in eqn 2.
5*Marty + Marty = 55
Marty = 55/6 years
---
Maria = 275/6 years

RELATED QUESTIONS

silvio is 10 years older than maria. The sum of their ages is equal to four times maria's (answered by ewatrrr)
Jeff is 7 years older than Marty. The sum of their ages is 71. How old is... (answered by ankor@dixie-net.com,MathTherapy)
mario is four years older than pedro the sum of their age is 40 how old are... (answered by lenny460)
Maria is 3 years younger than Francisco. Gabe is twice as old as Maria. Kiley is four... (answered by sachi,MathTherapy)
Ken is 6 years older than Maria. Maria is twice as old as Pedro. The sum of their age... (answered by josgarithmetic)
please help me solve this problem. jessie is 5 years older than ariane. four years from... (answered by stanbon)
maria is 3 years older than her brother, luis. luis is 2 years older than their younger... (answered by Fombitz)
kevin is 5 years older than maria. four times maria's age is 2 more than twice kevin's... (answered by ewatrrr)
Susan is four times as old is Maria. Five years from the sum of their ages will be 50.... (answered by Alan3354)