SOLUTION: Father is five less than four times his son's age.
Eight years from now, the father will be three more than twice his son's age.
How old are they now?
Algebra.Com
Question 1093627: Father is five less than four times his son's age.
Eight years from now, the father will be three more than twice his son's age.
How old are they now?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
f=4s-5
f+8=2(s+8)+3
4s-5+8=2(s+8)+3
4s+3=2s+16+3
2s=16
s=8
f=4s-5
f=27
check
f+8=2(s+8)+3
27+8=2*(16)+3
35=35
ok
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