SOLUTION: The age of a man is twice the sum of the ages of his two sons, and five year ago his age was thrice the sum of their ages. Find the man's present age.

Question 1093275: The age of a man is twice the sum of the ages of his two sons, and
five year ago his age was thrice the sum of their ages. Find the
man's present age.

Answer by Edwin McCravy(20056) (Show Source): You can put this solution on YOUR website!

Let S = the SUM of the two sons.

The age of a man is twice the sum of the ages of his two sons,

So the age of the man = 2S

and five year ago his age...

His age five years ago was 2S-5

...was...

equals

thrice

3 times

the sum of their ages.

S-10  [Why 10?  Because there are two sons and we must subtract
      [ 5 two times, once for each son. 

2S-5 = 3(S-10)

Solve that for S.  Then substitute what you get
for S in 2S to find the present age of the man.

Edwin

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