SOLUTION: The average age of a family of eight is 30 years. The average of six children in the family is 9 years. If the mother is four years younger than the father, calculate the age of th

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Question 1088814: The average age of a family of eight is 30 years. The average of six children in the family is 9 years. If the mother is four years younger than the father, calculate the age of the father.
Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52803)   (Show Source): You can put this solution on YOUR website!
.
1.  First step is to find the total age of all members of the family.

    It is 30*8 = 240 years.


2.  Second step is to find the total age of all children.

    It is 6*9 = 54.


3.  Now yo can calculate the total age of parents.

    It is 240 - 54 = 186.


4.  "the mother is four years younger than the father":  M = F - 4.


5.  From n.3, M + F = 186.

    Substitute M = F - 4 from n.4.  You will get

    (F-4) + F = 186,

    2F - 4 = 186  ====>  2F = 190  ====>  F =  = 95 Years.


Answer. Father is 95 years old.


My opinion is that this condition is absurd. Nonsense, in other words.



Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
m, Mother
f, Father
m=f-4


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