SOLUTION: Clayton is 6 years younger than his brother Josh. If the sum of their ages is
38​, how old is each​ boy?
Algebra.Com
Question 1088476: Clayton is 6 years younger than his brother Josh. If the sum of their ages is
38, how old is each boy?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
J - C = 6
J + C = 38
---------------- Add
RELATED QUESTIONS
clayton is 4 years younger than his brother josh. if the sum of their ages is 28, how old (answered by addingup)
Clayton is 2 years younger than his brother Josh. If the sum of their ages is 20, how old (answered by algebrahouse.com,stanbon)
Clayton is 6 years younger than his brother josh. If the sum of their age is 24,how old... (answered by josgarithmetic)
Clayton is 2 years younger than his brother Josh. If the sum of their age is 34,how old... (answered by ikleyn)
Steve is 7 years younger than his brother Richard. If the sum of their ages is 37 years,... (answered by josgarithmetic)
The difference in ages between a boy and his younger brother is 6years.the younger... (answered by ankor@dixie-net.com,MathTherapy,josgarithmetic)
Marvin is 22 years older than his younger brother Raul. In 6 years, the sum of their ages (answered by VFBundy,mila nedic,MathTherapy)
Josh and Sam have ages that are consecutive odd integers.The product of their ages is... (answered by josmiceli)
A boy is half as old as his sister and two years younger than this brother. The sum of... (answered by rfer)