SOLUTION: Celia is 2 times Jacque’s age now. Celia was 6 times Jacque’s age 9 years ago. What system of equations can be solved to find their ages?
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Question 1087117: Celia is 2 times Jacque’s age now. Celia was 6 times Jacque’s age 9 years ago. What system of equations can be solved to find their ages?
Found 3 solutions by Boreal, josmiceli, ikleyn:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
J age 9 years ago was x, and it is now x+9
C's age 9 years ago was 6x, and it is now 6x+9
But 6x+9=2(x+9), since C's age is twice J's age
6x+9=2x+18
4x=9
x=2.25
6x=13.5
today,
x=11.25, 9+2.25
2x=22.5, 9+13.5
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = Celia's age now
Let = Jacque's age now
----------------------------
(1)
(2)
----------------------------
(2)
(2)
Plug (1) into (2)
(2)
(2)
(2)
and
(1)
(1)
(1)
Jacque is 11 and 3 months
Celia is 22 and 6 months
---------------------
check:
(2)
(2)
(2)
(2)
Answer by ikleyn(52803) (Show Source): You can put this solution on YOUR website!
.
This formulation is DEFECTIVE, since has no integer solution for ages in years.
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