SOLUTION: This is my question, I am Richard and I am X year old. My father is three times my age, my mother is 2 years younger than my father and my sister is 1 year older than me. The total

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Question 1081423: This is my question, I am Richard and I am X year old. My father is three times my age, my mother is 2 years younger than my father and my sister is 1 year older than me. The total of our ages is 103. Form an equation in X and solve it to find the age of every member of the family. Also can you give me the working if it is no trouble.
Answer by htmentor(1343)   (Show Source): You can put this solution on YOUR website!
Richard = X [years old]
Father = 3X [3 times Richard's age]
Mother = 3X - 2 [2 years younger than Father]
Sister = X + 1 [one year older than Richard]
The sum of the ages is 103:
X + 3X + 3X - 2 + X + 1 = 103
Now solve for X:
8X - 1 = 103
X = 104/8 = 13
So Richard is 13 years old. The other ages can be computed from the relationships above.

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