SOLUTION: Of 2 women, Jayde and Anne, Anne is currently 3 times as old as Jayde. 10 years ago she was 5 times as old as Jayde. What are their current ages?

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Question 1073058: Of 2 women, Jayde and Anne, Anne is currently 3 times as old as Jayde.
10 years ago she was 5 times as old as Jayde. What are their current ages?

Found 2 solutions by ikleyn, josmiceli:
Answer by ikleyn(52813)   (Show Source): You can put this solution on YOUR website!
.
The condition produces these two equations for the women's current aje

A = 3J,               (1)
A - 10 = 5*(J-10).    (2)

Substitute an expression A = 3J of (1) into (2) to get

3J - 10 = 5(J-10),

3J - 10 = 5J - 50,

50 - 10 = 5J - 3J,

40 = 2J   --->  J =  = 20.

Answer.  Jayde is currently 20 years old. Anny is 3*20 = 60 years old.

There is a bunch of lessons on age word problems
    - Age problems and their solutions
    - A fresh formulation of a traditional age problem
    - Really intricate age word problem
    - Selected age word problems from the archive
in this site.

Read them and become an expert in solving age problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Age word problems".


Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
Let = Jayde's age now
Let = Anne's age now
-------------------------------
(1)
(2)
----------------------------
(2)
(2)
By substitution:
(2)
(2)
(2)
and
(1)
(1)
(1)
--------------------
Jayde's age now is 20
Anne's age now is 60
------------------------
check:
(2)
(2)
(2)
(2)
OK

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