SOLUTION: the sum of four consecutive even integers is 2 more than 5 times the first integer. Find the smallest integer.

Question 1064375: the sum of four consecutive even integers is 2 more than
5 times the first integer. Find the smallest integer.
Answer by Edwin McCravy(20056) (Show Source): You can put this solution on YOUR website!
the sum of four consecutive even integers is 2 more than
5 times the first integer. Find the smallest integer.



first (smallest) even integer = n
second even integer = n+2
third even integer = n+4
fourth even integer = n+6

the sum of four consecutive even integers is 2 more than
5 times the first integer.

n+(n+2)+(n+4)+(n+6) = 5n+2 Find the smallest integer. Solve for n. Edwin

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