SOLUTION: Sean is 26 years old. He is 8 years older than John. How many years ago was Sean's age three time John's age?

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Question 1062269: Sean is 26 years old. He is 8 years older than John. How many years ago was Sean's age three time John's age?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
s=26
s=j+8
-



Current ages are .


x, how many years ago






Current ages s and j are already solved or known now, so substitute.








Fourteen years ago

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Sean is 26 years old. He is 8 years older than John. How many years ago was Sean's age three time John's age?
Since Sean is 26, and is 8 years older than John, then John is 26 - 8, or 18 years-old.
Let years ago that Sean was 3 times John's age, be y
We then get: 26 - y = 3(18 - y)
26 - y = 54 - 3y
- y + 3y = 54 - 26
2y = 28
y, or years ago that Sean was 3 times John's age =
See how easy that was....nothing COMPLEX or CONFUSING!
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