SOLUTION: Jennifer is 6 years older than Sue. In 4 years, she will be twice as old as Sue was 5 years ago. Find their ages now.
Algebra.Com
Question 1061431: Jennifer is 6 years older than Sue. In 4 years, she will be twice as old as Sue was 5 years ago. Find their ages now.
Answer by LynnMomo(10) (Show Source): You can put this solution on YOUR website!
Let Sue's age be x
Then,Jennifer's age be x+6
In 4 years:
(X+6+4)÷2= x-5
(X+10)÷2= x-5
X+10= 2×(x-5)
X+10=2x-10
X-2x=-10-10
-x= -20
X= 20
Sue's age now is 20
Jennifer's age now is 20+6=26.
Gook luck on your study.^_^
RELATED QUESTIONS
Jennifer is 6 years older than Sue. In 4 years, she will be twice as old as Sue was 5... (answered by edjones)
Jennifer is 6 years older than Sue. In 4 years, She will be twice as old as Sue was 5... (answered by richwmiller)
jennifer is 6 years older than sue. in 4 years, she will be twice as old as sue was 5... (answered by oberobic)
jenifer is 6 years older than sue. in 4 years she will be twice as old as sue was 5 years (answered by solver91311)
jen is 6 years older than sue. in 4 years, she will be twice as old as sue was 5 years... (answered by palanisamy,dabanfield)
How do I solve by using a system of two equations in two variables?
Jennifer is 6... (answered by checkley77)
This question is from a worksheet. We do not have a textbook.
Jennifer is 6 years older (answered by josmiceli)
Please help! I'm totally stuck...
Jennifer is four years older than her sister, Sue. In (answered by checkley77,scott8148)
Help me solv this?
Jennifer is six years older than Sue. In four years she will be twice (answered by ptaylor)